x^2-16x=+63

Solution for x^2-16x=+63 equation:

x^2-16x=+63

We move all terms to the left:

x^2-16x-(+63)=0

We add all the numbers together, and all the variables

x^2-16x-63=0

a = 1; b = -16; c = -63;
Δ = b2-4ac
Δ = -162-4·1·(-63)
Δ = 508
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{508}=\sqrt{4*127}=\sqrt{4}*\sqrt{127}=2\sqrt{127}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{127}}{2*1}=\frac{16-2\sqrt{127}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{127}}{2*1}=\frac{16+2\sqrt{127}}{2}
$